Given two sorted integer arrays A and B, merge B into A as one sorted array.
Note:
You may assume that A has enough space (size that is greater or equal to m + n) to hold additional elements from B. The number of elements initialized in A and B are mand n respectively.
You may assume that A has enough space (size that is greater or equal to m + n) to hold additional elements from B. The number of elements initialized in A and B are mand n respectively.
用倒序的方法从大到小排列,i = m+n-1 注意for循环内都是if语句 时间O(m+n)
public class Solution {
public void merge(int A[], int m, int B[], int n) {
int j = m - 1;
int k = n - 1;
for (int i = m + n - 1; i >= 0; i--){
if (k >= 0 && j >= 0){
if (A[j] > B[k]){
A[i] = A[j];
j--;
} else {
A[i] = B[k];
k--;
}
} else if (k >= 0){
A[i] = B[k];
k--;
} else {// 这个else判定可以没有 因为此时i==j
A[i] = A[j];
j--;
}
}
}
}
public class Solution {
public void merge(int[] nums1, int m, int[] nums2, int n) {
int index = m + n - 1;
int i = m - 1;
int j = n -1;
while (i >= 0 && j >= 0) {
if (nums1[i] > nums2[j]) {
nums1[index] = nums1[i];
i--;
index--;
} else {
nums1[index] = nums2[j];
j--;
index--;
}
}
while (j >= 0) {
nums1[index] = nums2[j];
j--;
index--;
}
}
}
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