Given an array of n positive integers and a positive integer s, find the minimal length of a subarray of which the sum ≥ s. If there isn't one, return 0 instead.
For example, given the array
the subarray
[2,3,1,2,4,3]
and s = 7
,the subarray
[4,3]
has the minimal length under the problem constraint.
用滑动窗口的做法
public class Solution { public int minSubArrayLen(int s, int[] nums) { if (nums == null || nums.length == 0) { return 0; } int left = 0; int right = 0; int sum = 0; int min = Integer.MAX_VALUE; while (right < nums.length) { sum += nums[right]; while (sum >= s) { sum -= nums[left]; min = Math.min(min, right - left + 1); left++; } right++; } if (min == Integer.MAX_VALUE) { return 0; } else { return min; } } }
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