Given an integer n, count the total number of digit 1 appearing in all non-negative integers less than or equal to n.
For example:
Given n = 13,
Return 6, because digit 1 occurred in the following numbers: 1, 10, 11, 12, 13.
Given n = 13,
Return 6, because digit 1 occurred in the following numbers: 1, 10, 11, 12, 13.
思路: http://blog.csdn.net/xudli/article/details/46798619
public class Solution {
public int countDigitOne(int n) {
int res = 0;
for (long m = 1; m <= n; m*= 10) {
long a = n / m;
long b = n % m;
res += (a + 8) / 10 * m;
if (a % 10 == 1) {
res += b + 1;
}
}
return res;
}
}
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