Given a list of non negative integers, arrange them such that they form the largest number.
For example, given
[3, 30, 34, 5, 9], the largest formed number is 9534330.
Note: The result may be very large, so you need to return a string instead of an integer.
对于arraylist 用Collection.sort(arraylist, comparator) array用 Arrays.sort(array, comparator)
a.compareTo(b) 如果a大 return +, 小return - , eq return=
public class Solution {
public String largestNumber(int[] nums) {
if (nums == null || nums.length == 0) {
return "";
}
String[] str = new String[nums.length];
for (int i = 0; i < nums.length; i++) {
str[i] = String.valueOf(nums[i]);
}
Arrays.sort(str, new Comparator() {
public int compare(String s1, String s2) {
String l1 = s1 + s2;
String l2 = s2 + s1;
return l2.compareTo(l1);//为了使数值大的排在前面
}
});
StringBuilder sb = new StringBuilder();
for (String s : str) {
sb.append(s);
}
if (sb.charAt(0) == '0') {
return "0";
}
return sb.toString();
}
}
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