You are given an n x n 2D matrix representing an image.
Rotate the image by 90 degrees (clockwise).
Follow up:
Could you do this in-place?
Could you do this in-place?
思路是先把matrix按照对角线翻转 再按照垂直翻转 时间 O(n * n)
1 2 3 1 4 7 7 4 1
4 5 6 --> 2 5 8 -- > 8 5 2
7 8 9 3 6 9 9 6 3
1 2 3 1 4 7 7 4 1
4 5 6 --> 2 5 8 -- > 8 5 2
7 8 9 3 6 9 9 6 3
public class Solution {
public void rotate(int[][] matrix) {
int n = matrix[0].length;
int temp;
for(int i = 0; i < n; i++){
for(int j = i+1; j < n; j++){
temp = matrix[i][j];
matrix[i][j] = matrix[j][i];
matrix[j][i] = temp;
}
}
for(int i = 0; i < n; i++){
for(int j = 0; j < n/2; j++){
temp = matrix[i][j];
matrix[i][j] = matrix[i][n-1-j];
matrix[i][n-1-j] = temp;
}
}
}
}
public class Solution {
public void rotate(int[][] matrix) {
if(matrix == null || matrix.length==0 || matrix[0].length==0) {
return;
}
int n = matrix.length;
for (int i = 0; i < n; i++) {
for (int j = i; j < n - 1 - i; j++) {
int tem = matrix[i][j];
matrix[i][j] = matrix[n - 1 - j][i];
matrix[n - 1 - j][i] = matrix[n - 1 - i][n - 1 - j];
matrix[n - 1 - i][n - 1 - j] = matrix[j][n - 1 - i];
matrix[j][n - 1 - i] = tem;
}
}
}
}
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